Im trying to add another buffer to a program but it only prints one character im
trying to make a monster prorgam full of all sorts of code but im starting with using
strings and arrays for my own rube goldberg program a bunch of simple task but
the program only prints once character i want to know why.
.386
.model flat,c
.stack 100h
includelib msvcrt
.data
printf proto arg:ptr byte
string byte "Abby","Fred","john","kent","Mary",0
buffer byte 20 dup(?),0
buffer2 byte 4 dup(?),0
.code
public main
main proc
mov ecx,5
lea esi,string
lea edi,buffer
cld ;set the direction flag to decrement
;ecx instead increment
while1: cmp ecx,0
je endloop
push ecx
mov ecx,4
rep movsb
mov ecx,0
while2: cmp ecx,4
je endloop2
mov ebx, offset buffer
mov edx, offset buffer2
mov al,[ebx]
mov [edx],al
inc ebx
inc edx
endloop2:nop
invoke printf,addr buffer2
pop ecx
dec ecx
jmp while1
endloop:invoke printf,addr buffer
ret
main endp
end main
i want to copy what has already been stored in one of the buffers to another buffer how can i do this in the simplest way
im trying to nest loops can it be done
hellfix,
Yes you can have nested loops, but I'm not sure that you can do it with the HLL constructs.
Dave.