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Problem in finding DMA presence

Started by waqar ahmad, October 21, 2013, 07:54:33 AM

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waqar ahmad

Problem in ax or bx register values....
condition is not working  in both cases true or false it is jumping  to DMA_N


; Check DMA is present or not

dosseg
.model small
.stack 100h

.data
int 11h

DMA_ON   db  'DMA_Present', 0dh, 0ah, '$'
DMA_OF   db  'DMA_NOT_Present', 0dh, 0ah, '$'
.code
main proc
mov ax,@data
mov ds,ax

;to check bit number 8 in ax
mov bx,100h

and bx,ax
cmp bx,0 ; if i change : cmp bx,1
jne DMA_N ; In both cases 0 or 1 it jumps to DMA_N ?

mov ah,9
mov dx,offset DMA_OF ;DMA is not persent
    int 21h     ; Print the character

DMA_N:
mov ah,9
mov dx,offset DMA_ON ;DMA is persent
    int 21h     ; Print the character


    mov ax,4C00h  ;terminate program
    int 21h
main endp
end main

dedndave

the INT 11h instruction cannot be in the data segment

        .CODE

main    PROC

        mov     ax,@data
        mov     ds,ax

        int     11h
        mov     dx,offset DMA_ON
        test    ax,100h
        jnz     ShowResult

        mov     dx,offset DMA_OFF

ShowResult:
        mov     ah,9
        int     21h

        mov     ax,4C00h
        int     21h

main    ENDP

waqar ahmad

I have another program which is working fine :

; Check Co-Processor is present or not

dosseg
.model small
.stack 100h

.data
int 11h

CProcessor_ON   db  'Co-Processor_Present', 0dh, 0ah, '$'
CProcessor_OF   db  'Co-Processor_NOT_Present', 0dh, 0ah, '$'
.code
main proc
mov ax,@data
mov ds,ax


;to check bit number 1 in ax
mov bx,2h

and bx,ax
cmp bx,0 ; if i change : cmp bx,1
jne CPN ; In both cases 0 or 1 it jumps to Co-Processor_N ?

mov ah,9
mov dx,offset CProcessor_OF ; Co-Processor is not persent
    int 21h      ; Print the character
jmp ter

CPN:
mov ah,9
mov dx,offset CProcessor_ON ; Co-Processor is persent
    int 21h      ; Print the character

ter:
    mov ax,4C00h  ;terminate program
    int 21h
main endp
end main

dedndave

well - it's not working fine - you just think it is   :biggrin:

by the way...
as far as i know, all IBM PC compatibles have DMA
and - all modern ones have a "math co-processor"

MichaelW

Bit 8 of the equipment list word is unused for a normal PC. Per the Ralf Brown Interrupt List it was used only for the PCjr and for several Tandy models.

BTW, you can AND AX with an immediate value, specifying the immediate value by one of several different methods and then jump based on the state of the zero flag. For example:

    and ax, 1
    jz  bit0clear
    and ax, 10b       ; specify value in base 2
    jz  bit1clear
    and ax, 1 SHL 2   ; using SHL operator, result is 0100b
    jnz bit2set


Or instead of AND you can use the TEST instruction to avoid changing the value in AX. And note that virtually any interrupt you call will change the value in AX, and likely other registers, so depending on where you use a value in a register you may need to preserve it around the interrupt calls.

Well Microsoft, here's another nice mess you've gotten us into.

dedndave

...also....
most anything you can get with INT 11h, you can also get by accessing the BIOS data segment at 40h
you can reference Ralf for the the values in that segment, or use one of several other online references

http://www.bioscentral.com/misc/bda.htm#

that list reports that the word at offset 0040:0010, bit 8 is "reserved"
(same as byte at 0040:0011, bit 0)