mov eax, 12345678h mov loads a value into a register (note: 12345678h is a hex value because of the 'h' suffix)
mov cl, ah move the high byte of ax (67h) into cl (error here)
sub cl, 10 substract 10 (dec.) from the value in cl
mov al, cl and store it in the lowest byte of eax.
This was in the tutorial but looks like a typo, correct me if I'm wrong, isn't 56 = ah and 78 al and ax would be 5678h?
Thanks.
12345678h
12 34 56 78
AH = 56h, initially, not 67h
mov eax,12345678h
mov cl,ah ;CL = 56h = 86 decimal
sub cl,10 ;CL = 76 = 4Ch
mov al,cl ;EAX = 1234564Ch
So the tutorial had an error, thanks for the clarification.
I love this forum, just wish I had more time to read!
well - someone had an error
Quotemov cl, ah move the high byte of ax (67h) into cl (error here)
they grabbed the 6th and 7th character by accident
it should be the 5th and 6th