Exagone Tutorial question

[j00n]

mov eax, 12345678h mov loads a value into a register (note: 12345678h is a hex value because of the 'h' suffix)
mov cl, ah move the high byte of ax (67h) into cl (error here)
sub cl, 10 substract 10 (dec.) from the value in cl
mov al, cl and store it in the lowest byte of eax.

This was in the tutorial but looks like a typo, correct me if I'm wrong, isn't 56 = ah and 78 al and ax would be 5678h?

Thanks.

[dedndave]

12345678h
12 34 56 78

AH = 56h, initially, not 67h

Code Select Expand

    mov     eax,12345678h
    mov     cl,ah                          ;CL = 56h = 86 decimal
    sub     cl,10                          ;CL = 76 = 4Ch
    mov     al,cl                          ;EAX = 1234564Ch

[j00n]

So the tutorial had an error, thanks for the clarification.

I love this forum, just wish I had more time to read!

[dedndave]

well - someone had an error

mov cl, ah move the high byte of ax (67h) into cl (error here)

they grabbed the 6th and 7th character by accident
it should be the 5th and 6th